I am trying to calculate the power loss of a Kyocera solar panel. There is a temperature coefficient of the open circuit voltage of -.08 V/C and temperature coefficient of the short circuit current of .00502 A/C. I am not sure how to relate these two coefficients with the power loss.
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April 6, 2011 3:04 p.m. 93EXCivic SuperDork
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April 6, 2011 3:09 p.m. JThw8 SuperDork
sent link to our local electrical engineer/boy genius Tetzoe...he'll know the answer :)
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April 6, 2011 3:23 p.m. John Brown SuperDork
UH OH... Another Motorsports Marketing title is born!
CIRCUITS! FOR THE HARDCORE VOLTAGE ENTHUSIAST!
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April 6, 2011 11:31 p.m. RXBeetle Reader
If volts open circuit and amps for short circuit are given I would think that they are leading you toward a Thevenin equivalent circuit. R-thevenin / R-load *100 is power transfer efficiency.
