My wife is trying to figure out the last few problems in her math homework. Any math geeks here wanna try and help?
Ok....I need help....f f(x)=the sqare root of x+4 and G(x)= 2-x find the simplified equation for H(x)=(f(g(x))
Quoted from her fb page.
Thanks guys
If by f(x) you mean sqrt(x+4), then:
H(x) = sqrt(2-x+4) = sqrt(6-x).
OTOH, if by f(x) you mean sqrt(x)+4, then:
H(x) =sqrt(2-x)+4.
In other words, to find f(g(x)), just plug in g(x) for x in f.
not sure, I told her to long in and reply, she's at work, I'm at home, fixing to goto bed. lol 2:30am just comes waaay to early
billy3esq wrote:If by f(x) you mean sqrt(x+4), then:
H(x) = sqrt(2-x+4) = sqrt(6-x).
OTOH, if by f(x) you mean sqrt(x)+4, then:
H(x) =sqrt(2-x)+4.
In other words, to find f(g(x)), just plug in g(x) for x in f.
billy3esq wrote:If by f(x) you mean sqrt(x+4), then:
H(x) = sqrt(2-x+4) = sqrt(6-x).
OTOH, if by f(x) you mean sqrt(x)+4, then:
H(x) =sqrt(2-x)+4.
In other words, to find f(g(x)), just plug in g(x) for x in f.
THANK YOU I was looking for the sqrt of (X+4) :)
F(x)=sqrt (x) +4 G(x)=2-x=-x+2 H(x)= F(G(x))
Substitute y = G(x). H(x)=F(G(x))=F(y)
F(y)= sqrt (y) + 4 y=G(x)=-x+2
Substitute back.
F(y)= sqrt (y) + 4
F(G(X))=sqrt (G(x)) + 4 = sqrt (-x+2) +4.
F(G(X)) is imaginary if x >2.
Your inner ing-en-eer is coming out Billy3. You missing honest work?
Thanks again guys, I love this place!
It's better than disney! 
In reply to Spinout007:
Now I'm more confused...both would work...hrmm thanks guys...I hate math...give me english anyday:) Thanks I must say the answers here are much more logical than on fb
WIN! LMAO WOW! I LOVE IT! that dude was a trip,
We need a like button
Maxnscrappers wrote:We need a like button
LOL, hit the +1
lmao
In reply to Dr. Hess:
Not really, honest work is too hard.
For a second there, I thought it said meth help needed...
GRM does help with everything
Miata.
TL;DR
Bob Ross R.I.P. I initialy learned to oil paint from his show and books. And I suck at math.
LOL, my wife says she sucks at painting too.
speaking of math, check it out: http://www.neatorama.com/2010/04/08/try-this-and-prepare-to-be-amazed/
neatorama said:ake any number with 4 non-repeating digits. Say 1562.
Step 1: Arrange the number in ascending and then descending order Step 2: Subtract the smaller number from the bigger number
6521 - 1256 = 5265
Repeat the steps:
6552 - 2556 = 3996 9963 - 3699 = 6264 6642 - 2466 = 4176 7641 - 1467 = 6174
Try any 4-digit number with non-repeating digits, and you'll always get 6174.
Pretty cool, huh?
6174 is known as Kaprekar's constant. The math operation above, discovered by Indian mathematician D.R. Kaprekar, will reach 6174 after at most 7 steps (if you did more than 7 iterations, check your arithmetics).
solve for XR4Ti x 325xi (MX5) = $2011
Gearheadotaku wrote:solve for XR4Ti x 325xi (MX5) = $2011
Substitute LS1 and cancel interior, then divide by 2nd-hand race tires.
