Hi all,
I came across this website in my search for answers to calculating what master cylinder I need to replace the current setup in my car. I found a couple of posts that taught me something I didn't yet know, and my problem so far is that everywhere else people can't back up their suggestions with logic.
My situation is that I have a braking system that gives no feedback. It is fragile, and the parts are made of unobtanium. I currently have an issue, but the whole system needs to go.
I've done my research and my calculations, but the result doesn't look right to me. I'm humble enough to admit I muse be missing something, but so far no-one can tell me what.
I have a car that weighs 1200lbs on the front axle and 1700 on the rear, and a stock pedal ratio of 6.25:1. Lovely!
4 pots on the front with 2 38.1mm (diameter) pistons and 2 41.3mm (diameter) pistons each.
On the rear I have single pots at 36mm diameter. I've been told to expect 0.25mm of piston travel.
So...
((38.1mm x 0.25mm = 285.13cmm) x 4 = 1140.5ccm
((41.3mm x 0.25mm) = 335.05cmm) x 4 = 1340.2cmm
2480cmm aka 2.480 ccm for the front
((36.0mm x 0.25mm) = 254.57) x 2 = 509.2cmm
0.510 ccm for the rear
That's a total of 2.990 ccm, so let's call it 3ccm. And let's assume we will need some slack for pipe swell and that needing the whole pedal travel is not ideal and double it to 6ccm. Or 0.366cu.
The smallest bore master cylinder I have found (Wilwood TM1 5/8") will displace 6.6ccm or 0.4cu.
Is this correct? It seems odd to me that beefy brakes like that could be stopped by the smallest available bore.
I really hope it is, because 5/8" would require little force and allow me to do without a servo, and it should have a nice high psi too. But somehow I think I've missed something